
246738-YTG-B-0806
Unitary Products Group 5
FILTER PERFORMANCE
The airflow capacity data published in the “Blower Perfor-
mance” table listed above represents blower performance
WITHOUT filters. To determine the approximate blower per-
formance of the system, apply the filter drop value for the fil-
ter bein used or select an appropriate value from the “Filter
Performance” table shown below.
NOTE: The filter pressure drop values in the “Filter Perfor-
mance” table shown below are typical values for the type of
filter listed and should only be used as a uideline. Actual
pressure drop ratin s for each filter type vary between filter
manufacturer.
APPLYING FILTER PRESSURE DROP TO
DETERMINE SYSTEM AIRFLOW
To determine the approximate airflow of the unit with a filter in
place, follow the steps below:
1. Select the filter type.
2. Select the number of return air openin s or calculate the
return openin size in square inches to determine the
proper filter pressure drop.
3. Determine the External System Static Pressure (ESP)
without the filter.
4. Select a filter pressure drop from the table based upon
the number of return air openin s or return air openin
size and add to the ESP from Step 3 to determine the
total system static.
5. If total system static matches a ESP value in the airflow
table (i.e. 0.20, 0.60, etc,) the system airflow corre-
sponds to the intersection of the ESP column and Model/
Blower Speed row.
6. If the total system static falls between ESP values in the
table (i.e. 0.58, 0.75, etc.), the static pressure may be
rounded to the nearest value in the table determinin the
airflow usin Step 5 or calculate the airflow by usin the
followin example.
Exampl : For a 120,000 Btuh furnace with 2 return openin s
and operatin on hi h speed blower, it is found that total sys-
tem static is 0.58" w.c. To determine the system airflow, com-
plete the followin steps:
1. Obtain the airflow values at 0.50" & 0.60" ESP.
Airflow @ 0.50": 2285 CFM
Airflow @ 0.60": 2175 CFM
2. Subtract the airflow @ 0.50" from the airflow @ 0.60" to
obtain airflow difference.
2175 - 2285 = -110 CFM
3. Subtract the total system static from 0.50" and divide this
difference by the difference in ESP values in the table,
0.60" - 0.50", to obtain a percenta e.
(0.58 - 0.50) / (0.60 - 0.50) = 0.8
4. Multiply percenta e by airflow difference to obtain airflow
reduction.
(0.8) x (-110) = -88
5. Subtract airflow reduction value to airflow @ 0.50" to
obtain actual airflow @ 0.58" ESP.
2288 - 88 = 2197
RECOMMENDED FILTER SIZES
Input/Output
BTU/H CFM Cabin t
Siz
Sid R turn
Filt r in.
Bottom R turn
Filt r in.
40/38 1200 A 16 x 25 14 x 25
60/56 1200 B 16 x 25 16 x 25
80/75 1200 B 16 x 25 16 x 25
80/75 1600 C 16 x 25 20 x 25
100/93 1600 C 16 x 25 20 x 25
100/93 2000 C 16 x 25 20 x 25
120/112 2000 D (2) 16 x 25 22 x 25
FILTER PERFORMANCE - PRESSURE DROP INCHES W.C.
Airflow Rang
Minimum Op ning Siz Filt r Typ
Disposabl Washabl Fib rs Pl at d
1 Openin 2 Openin s 1 Openin 2 Openin 1 Openin 2 Openin 1 Openin 2 Openin
Sq. in. Sq. in. In w.c. In w.c. In w.c. In w.c. In w.c. In w.c.
0 - 750 230 0.01 0.01 0.15
751 - 1000 330 0.04 0.03 0.20
1001 - 1250 330 0.08 0.07 0.20
1251 - 1500 330 0.08 0.07 0.25
1501 - 1750 380 658 0.14 0.08 0.13 0.06 0.30 0.17
1751 - 2000 380 658 0.17 0.09 0.15 0.07 0.30 0.17
2001 & Above 463 658 0.17 0.09 0.15 0.07 0.30 0.17
UNIT CLEARANCES TO COMBUSTIBLES
Application Top Front R ar L ft Sid Right Sid Flu Floor/
Bottom
Clos t
Alcov Attic
In. In. In. In. In. In.
Upflow 1 3 0 0 0 0 Combustible Yes Yes