Casio fx-5800P Owner's manual

fx-5800P
 Tillägg
Supplement
Suplemento
Ergänzung
Supplemento
J E S G I Sw KCh C
k
http://edu.casio.jp/
http://world.casio.com/edu/
付録
RJA516833-001V01

– 1 –
1-1 mp1.67262171×10–27 kg 3-5
1-2 mn1.67492728×10–27 kg 3-6 F96485.3383 C mol –1
1-3 me9.1093826×10–31 kg 3-7 e1.60217653×10–19 C
1-4 m1.8835314×10–28 kg 3-8 NA6.0221415×1023 mol –1
1-5 a00.5291772108×10–10 m 4-1 k1.3806505×10–23 J K–1
1-6 h6.6260693×10–34 J s 4-2 Vm22.413996×10–3 m3mol –1
1-7 5.05078343×10–27 J T –1 4-3 R8.314472 J mol –1 K –1
1-8 927.400949×10–26 J T –1 4-4 C0299792458 m s–1
2-1 H1.05457168×10–34 J s 4-5 C13.74177138×10–16 W m2
2-2 α7.297352568×10–3 4-6 C21.4387752×10–2 m K
2-3 re2.817940325×10–15 m 4-7 σ5.670400×10–8 W m–2 K–4
2-4 λc2.426310238×10–12 m 4-8 ε08.854187817×10–12 F m–1
2-5 γp 2.67522205×108s–1 T–1 5-1 12.566370614×10–7 N A–2
2-6 λcp 1.3214098555×10–15 m 5-2 2.06783372×10–15 Wb
2-7 λcn 1.3195909067×10–15 m 5-3 g9.80665 m s–2
2-8 R∞10973731.568525 m–1 5-4 G07.748091733×10–5 S
3-1 u1.66053886×10–27 kg 5-5 Z0376.730313461 Ω
3-2 1.41060671×10–26 J T–1 5-6 t273.15 K
3-3 –928.476412×10–26 J T–1 5-7 G6.6742×10–11 m3kg–1 s–2
3-4 –0.96623645×10–26 J T–1
5-8 atm 101325 Pa
–4.49044799×10–26 J T –1
N
µ
B
µ
µ
p
µ
e
µ
n
µ
0
µ
µ
µ
0
φ
#01

– 2 –
#02
a=
n
Σyi–a.Σxi
b=
n.Σxi2–(Σxi)2
n.Σxiyi–Σxi.Σyi
r=
{n.Σxi2–(Σxi)2}{n.Σyi2–(Σyi)2}
n.Σxiyi–Σxi.Σyi
my–b
a
=
n=ax +b
#03
n
Σyi
c=–a
( )
–b
( )
n
Σxi
n
Σxi2
b=Sxx.Sx2x2
–(Sxx2)2
Sxy.Sx2x2 –Sx2y.Sxx2
a=Sxx.Sx2x2–(Sxx2)2
Sx2y.Sxx –Sxy.Sxx2
(Σxi)2
Sxx =Σxi
2–n
Sxy =Σxiyi–n
(Σxi .Σyi)
Sxx2=Σxi
3
–n
(Σxi.Σxi
2)
Sx2x2=Σxi
4
–n
(Σxi
2)2
Sx2y=Σxi
2yi–n
(Σxi
2.Σyi)
m1=2a
–b+b2–4a(c–y)
m2=2a
–b–b2– 4a(c–y)
n=ax2+bx+c
#04
a=n
Σyi–b.Σlnxi
b=n.Σ(lnxi)2–(Σlnxi)2
n.Σ(lnxi)yi–Σlnxi.Σyi
r=
{n.Σ(lnxi)2–(Σlnxi)2}{n.Σyi2–(Σyi)2}
n.Σ(lnxi)yi–Σlnxi.Σyi
m=e
y –a
b
n=a+blnx

– 3 –
a=exp
( )
n
Σlnyi–lnb.Σxi
b=exp
( )
n.Σxi2–(Σxi)2
n.Σxilnyi–Σxi.Σlnyi
r=
{n.Σxi2–(Σxi)2}{n.Σ(lnyi)2–(Σlnyi)2}
n.Σxilnyi–Σxi.Σlnyi
m=lnb
lny –lna
n=abx
a=exp
( )
n
Σlnyi–b.Σlnxi
b=n.Σ(lnxi)2–(Σlnxi)2
n.Σlnxilnyi–Σlnxi.Σlnyi
r=
{n.Σ(lnxi)2–(Σlnxi)2}{n.Σ(lnyi)2–(Σlnyi)2}
n.Σlnxilnyi–Σlnxi.Σlnyi
m=eb
lny– lna
n=axb
#05
#06
#07
a=exp
( )
n
Σlnyi–b.Σxi
b=n.Σxi2–(Σxi)2
n.Σxilnyi–Σxi.Σlnyi
r=
{n.Σxi2–(Σxi)2}{n.Σ(lnyi)2–(Σlnyi)2}
n.Σxilnyi–Σxi.Σlnyi
m=b
lny– lna
n=aebx

– 4 –
b=Sxx
Sxy
r=Sxx.Syy
Sxy
Sxx =Σ (xi–1)2–
Syy =Σyi2–
Sxy =Σ(xi–1)yi–
n
(Σxi–1)2
n
Σxi–1.Σyi
n
(Σyi)2
a=n
Σyi–b.Σxi–1
#08
m=y –a
b
n=a+x
b
1
2
3
4
5
tan =
θ
m2 –m1
1+m1m2
(m1m2G1)
a=t2–t1
(t2>t1>0)
a
b
c
A
BC
S
=
n{2a + (n – 1)d}
2
#09
θ
y
x
y=m2x+k2
y=m1x+k1
cos A=
2 bc
b2+ c2 – a2
cos B=
2 ca
c2+ a2 – b2
cos C=
2 ab
a2+ b2 – c2
2–1
υ υ
S= 0t + at2
1
2(t>0)
υ

– 5 –
6
7
8
9
[(xp, yp)→(Xp, Yp)]
Xp = (xp–x0)cos + (yp–y0)sin
Yp = (yp–y0)cos – (xp–x0)sin
α
α
10
11
12
= (M, T > 0)
3RT
M
[++Z =Const.]
P
γ2g
P2= P1+
γ
(
2g+ Z1– Z2
)
(υ, P, , Z > 0)
γ
[++Z =Const.]
P
γ
2
2g
2g(P1– P2)
γ
[++Z =Const.]
P
γ
Px= nCxPx( 1 – P)n–x
13
η
=Q1 – Q2
Q1
(Q1G0)
XP = Rcos
+ XA
α
YP = Rsin + YA
α
α
α
y
x
YX
(0, 0)
(x0,y0)
α
(xp,yp)(Xp,Yp)
(XA,YA)
(Xp,Yp)
(XB,YB)
α
R
υ
2
υ
12– 22
υυ
υ
+ 1
2+ 2g(Z1– Z2)
υ
( , P, , Z > 0)
γ
υ
2=
υ
2
2g
υ
γ
( , P, , Z > 0)
γ
υ
Z2= + + Z1
P1–P212
–22
2g
υυ
(
)
0 <P <1
x = 0, 1, 2······
Pol(XB – XA, YB – YA)

– 6 –
14
15
16
17
18
19
20
η
=T1– T2
T1
(T1G0)
F = mr 2
ω
(m, r,>0)
ω
F = mr
S0= rR
π
(r,R>0)
V= r2h(r, h >0)
1
3
π
S0= 2 rh
π
(r,h >0)
21
V= r2h
π
(r,h >0)
24
T=1
f(f > 0)
25
S= r2
π
(r >0)
22
T=2
ω
π
(G0)
ω
2
υ
= T
σ
( T,>0 )
σ
υ
23
T=2 r
υ
π
( G0)
υ
(r,m, >0)
υ
26
R=
ρ
R
S(S,R, > 0)
ρ
[ ]
[ ]
27
ρ
ρ
A111= A222 = Const.
υυ
ρ
28
A111= A222 = Const.
υ
ρ
υ
ρ
(2G0, 2> 0)
ρ
υ
(A2, 2> 0)
2=
υ
A2 2
ρ
A111
ρ
υ
A2=
A111
ρ
υ
2 2
ρ
υ

– 7 –
XP = Rcos
+ XA
α
YP = Rsin
+ YA
α
29
R1
=
R4R5+ R5R6+ R6R4
R5
R2
=
R4R5+ R5R6+ R6R4
R6
R3
=
R4R5+ R5R6+ R6R4
R4
(R4, R5, R6> 0)
30
R4
= , R5
R1R2
R1+ R2+ R3
= ,
R2R3
R1+ R2+ R3
R6
=
R3R1
R1+ R2+ R3
(R1, R2, R3> 0)
31
[(XA, YA), Rec(R, )→(Xp, Yp)]
α
32
a= b2+ c2– 2bc cos A
(b, c> 0, 0˚ < A< 180˚)
a2= b2+ c2– 2bc cos A →
b2= c2+ a2– 2ca cos B
c2= a2+ b2– 2ab cos C
33
r2
Qq
F=4 0
πε
1(r > 0)
34
S= 13+ 23+ ······ + n3=
{
}
2
n(n+ 1)
2
35
Ai [dB]= 20 log10 [dB]
(
)
Ι2
Ι1
(Ι2/ Ι1> 0)
36
σ
y = × 10 + 50
x – xA(> 0)
σ
(XA,YA)
(Xp,Yp)
α
R
X

– 8 –
υ
W= CV2
1
2
W= 1
2C
Q2
(C> 0)
Up= kx2(k, x > 0)
1
2
= 0t +
υ
Sgt2(t>0)
1
2
37
Pol(XB – XA, YB – YA)
38
f = f0
υυ
–0
– u
(
)
υ
G
υ
0,f0> 0, > 0
υυ
–0
υ
– u
39
40
41
42
43
W= QV
1
2
44
W= ED
1
2(E, D> 0)
45
W= E2
1
2(, E> 0)
εε
46
4 0r2
πε
Q
E= (= 9 × 109)
Q
r2(r > 0)
47
f =2
1
π
LC (L, C> 0)
48
S= ab (a, b >0)
π
a
b
(XA,YA)
(XB,YB)
αR
X
49
H= U + PV (U, P, V>0)

– 9 –
Px
=
(0 <k<N, 0 <n<N)
kCx · N –k C n –x
NCn
sin ic = (1 <n12)
1
n12
55
56 Ve = BR (, B,R> 0)
υυ
57 PnRT
V
= (n, T, V> 0)
58 VnRT
P
= (n, T, P> 0)
59 TPV
nR
= (P, V, n> 0)
60 nPV
RT
= (P, V, T> 0)
61
62 W= LI2(L, I> 0)
1
2
S= s(s– a)(s– b)(s– c), s= a+ b+ c
)
(
a+ b> c> 0
b+ c> a> 0
c+ a> b> 0
52
S= (rG1)
a (rn–1)
r – 1
53
Q= mcT
54
2
50
y = e– x x> 0
λ
λ
y = 0 x<0 (> 0)
λ
51
(
)
Px = ( 1 – P)x Px = 0, 1, 2······
0 < P <1