13
12
8) Rate of climb (or descent)
The rate of climb (or descent) can be obtained from the time required to reach
an altitude.
Example: Obtain the rate of climb when an aircraft reaches an altitude of 7,500
feet after climbing for 16 minutes.
Answer. Align “75”on the outer scale with “16”on the inner scale. Then,
“10”on the inner scale correspons to “47”on the outer scale. Thus,
the rate of climb is 470 per minute.
9) Time of climb (or descent)
The time required for climb can be obtained from the altitude to be reached and
the rate of climb (or descent).
Example: Obtain the time of climb when an aircraft is to climb to 6,300 feet at
a rate of 550 feet per minute.
Answer. Align “55”on the outer scale with “10”on the inner scale. Then,
“63”on the outer scale corresponds to “11.5”on the inner scale.
thus, the time of climb is 11 minutes and 30 seconds.
10) Conversion
Example: Convert 30 statuts miles into nautical miles and kilometers.
Operation: Align “30”on the outer scale with STAT (▲) on the inner scale.
Then, NAUT (▲) on the inner scale corresponds to “26”nautical
miles on the outer scale, and “12 km”(s) on the inner scale corre-
sponds to “48.2”km on the outer scale.
Answer. Align “25”on the outer scale with the SPEED INDEX (▲) on the
inner scale. Then, “6:00”on the inner scale (time scale) corresponds
to “15”on the outer scale. Thus, the fuel consumption is 1,500 gal-
lons.
6) Estimated flight time
Example: Obtain the estimated flight time when the vate of fuel consumption is
220 gallons per hour and the aircraft has 550 gallons of fuel.
Answer. Align “22”on the outer scale with the SPEED INDEX (▲) on the
inner scale. Then, “55”on the outer scale corresponds to “2:30”on
the inner scale (time scale), Thus, the estimated flight time is 2 hours
and 30 minutes.
7) Difference in altitude
The difference in altitude can be obtained from the rate of descent and the de-
scent time.
Example: Obtain the difference in altitude when an aircraft continues descend-
ing for 23 minutes at a rate of 250 feet per minute.
Answer. Align “25”on the outer scale with “10”on the inner scale. Then, “23”
on the inner scale corresponds to “57.5”on the outer scale. Thus, the
difference in altitude is 5,750 feet.