(8) Velocity at Outlet Piping
The PowerTrap uses the motive medium supply pressure to push out the condensate in the
trap.
• Discharge capacity of pumped medium for each discharge operation:
GP10L/GT10L :approximately 6 liters (1.6 U.S. gal)
GP14L/GT14L :approximately 8 liters (2.1 U.S. gal)
GP14M/GT14M :approximately 12.5 liters (3.3 U.S. gal)
• The amount of time required for each discharge operation will be between 3 and 30
seconds, depending on the back pressure and the motive medium pressure.
This means that the instantaneous flow through the pumped medium outlet pipe during the
discharge operation is between 0.7 and 23 metric tonnes (180 and 6000 U.S. gal) per hour.
• When a condensate flowmeter is to be installed in the pumped medium outlet piping, it
should be selected to reflect the intermittent operation and should be sized to
accommodate the maximum and minimum instantaneous flow. For details, contact TLV.
(9) For Closed Systems:
• An air vent (for steam) [La] or valve for air discharge [Va] is required to discharge the initial air
in the equipment and the reservoir pipe or any gas generated in the system. In this case,
installing the check valve for air vent [Ca] will prevent air from being sucked in from the outlet
of the vent pipe [Sv]. This check valve must be installed when the pressure inside the piping
becomes negative. A valve for air discharge [Va] can be installed instead of the air vent (for
steam) [La] and check valve for air vent [Ca].
When releasing the initial air using a valve for air discharge, leave the valve for air discharge
[Va] slightly open until the PowerTrap has cycled 2 – 3 times. Close the valve for normal
operation.
• Select the appropriate PowerTrap model (GT or GP) based on the explanation in “General
Description”.
• Refer to “(2) When flash steam is not involved” in “Sizing the Condensate Receiver/
Reservoir” for information on condensate reservoir sizing.
For more details, contact TLV.
Sizing the Condensate Receiver/Reservoir
When selecting the receiver/reservoir pipe for the PowerTrap, select from among the
following 3 conditions:
(1) When large quantities of flash steam are involved
(For open systems using steam)
a) Determine the amount of flash steam:
Amount of flash steam Fs = Q × (hd’ − hh’) / r
Fs : amount of flash steam (kg/h) (lb/h)
Q : amount of condensate (kg/h) (lb/h)
hd’: specific enthalpy (kJ/kg) (Btu/lb) of saturated condensate at condensate
inlet set pressure (Pi)
hh’: specific enthalpy (kJ/kg) (Btu/lb) of saturated condensate at
condensate receiver set pressure (P2)
r : specific enthalpy (kJ/kg) (Btu/lb) vaporization (latent heat of
steam) at condensate receiver set pressure (P2)
b) Determine the vent pipe diameter according to the amount of flash steam in Vented Receiver
Table - 1 shown on the next page.
c) Determine the overflow pipe diameter (Dop, refer to the figure below).
NOTE: The overflow pipe diameter should be at least as large as the condensate inlet pipe
diameter (Dcip, refer to the figure below).
d) Determine the minimum condensate receiver diameter (Dcr, refer to the figure below) by
selecting the largest value among those from (i), (ii), and (iii) based
on a condensate receiver length of 1 m (3.3 ft).
(i) is the overflow pipe diameter multiplied by 3 or more.
(ii) is the minimum receiver diameter according to the amount of flash
steam in Vented Receiver Table - 1 shown on the next page.
(iii) is the minimum receiver diameter according to the amount of
condensate in Vented Receiver Table - 2 shown on the next page.
NOTE: Receiver length can be reduced by 50% when the motive pressure (Pm)
divided by the back pressure (Pb) is ""2"" or greater. (Pm ÷ Pb ≥2)