II. INSTALLATION
CAUTION:
All external wiring must comply with applicable codes and local ordinances.
DO NOT connect power supply until air cleaner has been installed and/or checked.
A. HOW TO DETERMINE THE NUMBER OF ELECTRONIC AIR CLEANERS
REQUIRED
To determine the number of electronic aircleanersrequired for your business
establishments, use the method below as a guideline. If you have anyquestions, call the
LakeAir HOTLINE at 1-800-558-9436 and we will help you.
METHOD: SIZE BY ROOM VOLUME AND AIR CHANGES PER
HOUR
1. Calculate the volume of the room. Volume (cubic feet) = Length x Width x Height
2. Determine the circulation of the air needed, based upon 8 air changes per hour for average
conditions, to reduce the smoke and pollution. Use 16 air changes per hour for high concentrations
of smoke and contaminants, or when one has a desire to reduce smoke and pollution even further.
3. The LA-1400S and 2000S have differing capacities in cubic feet/minute. Both models are two
speed units with a high and a low speed of operation. The LA-1400S produces 800 cfm at low
speed and 1100 cfm at high speed. The LA-2000S produces 1500 cfm at low speed and 2100 cfm at
high speed. To establish the correct unit and/or number of units to use, you should calculate the
cubic feet of air in the area to be cleaned, and then use a figure of 8 air changes/hour in that area for
average cleaning, and 16 air changes per hour for very polluted or smoke filled conditions. You
shouldremember that the slower the air passes over the surface of the air cleaner, the more
efficiently the unit will operate. Therefore, when calculating the number of units needed, take into
account air flow and cleaning capacity.
EXAMPLE #1
ROOM DIMENSIONS:
TYPE OF AREA:
50’ X 100’ X 10’ CEILING
RESTAURANT OR LOUNGE
AIR CHANGES DESIRED: 16/HOUR
STEP 1 - VOLUME =50’ X 100’ X 10’ = 50,000 CU. FT.
STEP 2 - VOLUME TO BE CLEANED = 50,000 CU. FT. X 16 AIR CHANGES/HOUR
STEP 3 – VOLUME/MINUTE TO BE CLEANED = 800,000 CU.FT./HOUR = 13,333 CU.FT. MIN.(CFM)
60,000 MINUTES/HOUR
STEP 4 – NUMBER OF UNITS NEEDED = 13,333 CFM ÷ THE CFM OF THE CHOSEN UNIT
(MODEL LA-2000) =13,333 CFM = 6.34 OR 6 UNITS
2,100 CFM
(MODEL LA-1400) =13,333 CFM = 12.09 OR 12 UNITS
1,100 CFM
EXAMPLE #2
ROOM DIMENSIONS:
TYPE OF AREA:
50’ X 30’ X 10’ CEILING
OPEN OFFICE AREA WITH MULTIPLE PERSONNEL
AIR CHANGES DESIRED: SOME SMOKERS AND 20 DESKS – USE 8 AIR CHANGES/HOUR
STEP 1 – VOLUME =50’ X 30’ X 10’ = 15,000 CU.FT.
STEP 2 – VOLUME TO BE CLEANED = 15,000 CU.FT. X 8 AIR CHANGES/HOUR = 120,000 CU.FT./HOUR
STEP 3 – VOLUME/MINUTE TO BE CLEANED = 120,000 CU.FT./HOUR = 2,000 CU.FT./MINUTE(CFM)
60 MINUTES/HOUR
STEP 4 – NUMBER OF UNITS NEEDED = 2,000 CFM DIVIDED BY THE CFM OF THE CHOSENUNIT
(MODEL LA-2000)
(MODEL LA-1400)
= 2,000 CFM =1 UNIT
2,100 CFM
= 2,000 CFM = 1.8 OR 2 UNITS
1,
CFM100
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